Question

A cylinder contains 11.8 L of air at a total pressure of 41.4 psi and a temperature of 30 ∘C. How many moles of gas does the cylinder contain?

Answer 1

Answer:

P = 41.4 psi = 41.4×0.068 atm = 2.82 atm

(1psi = 0.068 atm)

V = 11.8 L

T = 30°C = 30 + 273.15 K = 303.15 K

R = 0.082 Latm/mol.K

n = PV/RT = 2.82×11.8/(0.082×303.15) mol

= 1.34 mol