Question

See attachment for the whole question.
One card is drawn from a well-shuffled deck of fifty-two cards
Find the probability of drawing a card below a 6 (count an ace as high). (Enter your answer as a fraction.)
(b) Find the odds of drawing a card below a 6 (count an ace as high).

Answer 1

Using probability concepts, it is found that:

a) $\frac{4}{13}$ probability of drawing a card below a 6.

b) $\frac{4}{9}$ odds of drawing a card below a 6.

c) We should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.

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• A probability is the number of desired outcomes divided by the number of total outcomes.

Item a:

• In a standard deck, there are 52 cards.
• There are 4 types of cards, each numbered 1 to 13. Thus, $4 \times 5 = 20$ are less than 6.

Then:

$p = \frac{20}{52} = \frac{4}{13}$

$\frac{4}{13}$ probability of drawing a card below a 6.

Item b:

• Converting from probability to odd, it is:

$\frac{4}{13 - 4} = \frac{4}{9}$

$\frac{4}{9}$ odds of drawing a card below a 6.

Item c:

• The law of large numbers states that with a large number of trials, the percentage of each outcome is close to it's theoretical probability.
• Thus, we should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.

A similar problem is given at https://brainly.com/question/24233657