Respuesta :
Newton's second law allows concentrating that the response for maximum acceleration of the system is equal to the acceleration of gravity (a = g)
Newton's second law states that the net force is proportional to the product of the mass and the acceleration of the body
F = m a
The bold letters indicate vectors, F is the force, m and the mass and acceleration of the body, respectively.
The reference system is a coordinate system with respect to which measurements are made, in this case let's set a system where the x-axis is horizontal and the positive part is in the direction of movement, the y-axis is vertical.
In the attached we can see a diagram of the indicated system, as it indicates that there is no friction force, we write the equations for each part
truck
T = Ma
Hanging masses
T- m g = m a
for the rope to stay taut, the acceleration must be the same. We solve the system
M a - m g = m a
a = [tex]\frac{m}{m+ M}[/tex] g
This is the acceleration of the truck. Let's analyze the different cases to shrink the maximum acceleration:
- The hanging mass is much greater than the mass of the truck (m> M), we neglect the more of the truck
a = g
- The hanging mass is less than the mass of the truck (m <M)
a = [tex]\frac{1}{1 + \frac{M}{m} }[/tex] g
a = ( [tex]1 + \frac{M}{m}[/tex] )⁻¹ g
The [tex]\frac{M}{m}[/tex] value is much greater than the integer, we despise it the integer
a = [tex]\frac{m}{M}[/tex] g
Since the truck mass is greater than the hanging mass, this acceleration is less than the acceleration of gravity.
a <g
In conclusion, using Newton's second law we can concentrate that the response for maximum acceleration of the system is equal to the acceleration of gravity (a = g)
Learn more about Newton's second law here:
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