Consider the line y=4x-4.
Find the equation of the line that is parallel to this line and passes through the point (3, 6).
Find the equation of the line that is perpendicular to this line and passes through the point (3, 6).

Respuesta :

9514 1404 393

Answer:

  • parallel: y = 4x -6
  • perpendicular: y = -1/4x +27/4

Step-by-step explanation:

If we want the new line to be written in slope-intercept form, we need to find the new value of the y-intercept. The equation of the line is ...

  y = mx +b . . . . . . . for slope m and y-intercept b

Solving for b gives ...

  b = y -mx . . . . . . . subtract mx from both sides.

The values of x and y come from the point we want the line to pass through. The value of m will be the same for the parallel line as for the given line: 4. For the perpendicular line, it will be the opposite reciprocal of this: -1/4.

Parallel line

  b = 6 -4(3) = 6 -12 = -6

  y = 4x -6

Perpendicular line

  b = 6 -(-1/4)(3) = 6 +3/4 = 27/4

  y = -1/4x +27/4

Ver imagen sqdancefan
ACCESS MORE