Question

Tin reacts with Fluorine to form two different compounds, A and B. Compounds A contains 77.0 g tin for each 24.6 g of fluorine. Compound B contains 113.0 g of tin for each 72.4 g of fluorine. What is the lowest whole number mass ratio of tin that combines with a given mass of fluorine?

Answer 1

A contains 38.5 g of tin for each 12.3 g of fluorine: 
mole ratio: 
(38.5 g)/(118.71 g/mol):(12.3 g)/(18.998 g/mol) = 0.324:0.647 = 1:2 ⇒ SnF₂ 

B contains 56.5 g of tin for each 36.2 g of fluorine: 
mole ratio: 
(56.5 g)/(118.71 g/mol):(36.2 g)/(18.998 g/mol) = 0.476:1.905 = 1:4 ⇒ SnF₄

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Answer 2

Answer: The lowest whole number mass ratio of tin is 2 : 1

Explanation:

We are given:

• In Compound A:

Mass of fluorine = 24.6 g

Mass of Tin = 77.0 g

• In Compound B:

Mass of fluorine = 72.4 g

Mass of Tin = 113.0 g

As, the mass of fluorine is fixed in both the compounds.

Taking compound B:

If 72.4 grams of fluorine is reacting with 113.0 grams of Tin

So, 24.6 grams of fluorine will react with = $\frac{113}{72.4}\times 24.6=38.4g$ of Tin

Now, taking the ratio of tin from both the compounds:

$\Rightarrow Sn_A:Sn_B=77.0:38.4\\\\\Rightarrow Sn_A:Sn_B=2:1$

Hence, the lowest whole number mass ratio of tin is 2 : 1