Question

Solve each problem. Show your solution. (5 points each)
x2+x-6x2-3x-4≤0

Answer 1

Step-by-step explanation:

• we first start by making things understandable.
• (2x+x-6)(2-3x-4)≤0
• (3x-6)(-3x-2)≤0
• we then multiply
• 3x(-3x-2)-6(-3x-2)≤0
• -9x^2-6x+18x+12≤0
• -9x^2+12x+12≤0
• we divide by -1 because we can't have a negative squared number
• Therefore: 9x^2-12x-12≤0
• we then open bracket
• (3x-12)(3x+1)≤0
• Therefore 3x-12=0 or 3x+1=0
• 3x=12 or 3x=-1
• we divide by 3 both side
• x=4 or x=0.3
• Therefore 4≤x≤0.3