Answer:
(x+1)(x+2)(x-3)
x³-7x-6
Step-by-step explanation:
We are looking for an equation where we have a degree of 3 and where we can plug in -1, -2, or 3 for x and have it equal 0
the first one is definetly correct
To see if there's another answer let's mulitply it out
(x+1)(x+2)(x-3)= (x-3)(x²+3x+2)= x³-7x-6 which is equal to the third one
