Question

Calculate the freezing point of 0.5g of biphenyl in 20.0mL of cyclohexane. Cyclohexane Fp = 6.5 Celsius Kf 20.01

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Answer 1

We have that the freezing point of 0.5g of biphenyl in 20.0mL of cyclohexane. Cyclohexane Fp = 6.5 Celsius Kf 20.01

$X=6.5-5$

$X=1.5$

From the question we are told

Calculate the freezing point of 0.5g of biphenyl in 20.0mL of cyclohexane. Cyclohexane Fp = 6.5 Celsius Kf 20.01

Generally We Know that

Freezing Point of cyclohexane is 6.5ºC

Kf for cyclohexane is 20ºC/m

Density of cyclohexane is 0.779 g/mL

Generally the equation for the   is mathematically given as

$C6H12_{mass} = 20 x 0.78 \\\\C6H12_{mass} = 15.6g$

Therefore

$Solution's\ Molality=\frac{0.6g }{154g}\\\\Solution's\ Molality = 0.25m$

Therefore

$\lambda= Cf\ x\ m\\\\\lambda= 20 x\ 0.25\\\\\lambda= 5$

Therefore

The freezing point of 0.5g of biphenyl in 20.0mL of cyclohexane. Cyclohexane Fp = 6.5 Celsius Kf 20.01

$X=6.5-5$

$X=1.5$

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