Question

The elemental analysis of a substance is 37.51% C, 3.15% H, and 59.34% F. Based on the elemental analysis and the mass
spectrum provided, what is the molecular formula?

Answer 1

The molecular formula of the compound whose elemental analysis and mass spectrum are shown  is C2H2F2.

First we divide the percentage by mass of each element by its relative atomic number;

C - 37.51/12,      H -  3.15/1,         F - 59.34/19

C - 3.12,            H - 3.15,             F - 3.12

Divide through by the lowest ratio;

C - 3.12/3.12,    H - 3.15/3.12    F- 3.12/3.12

C - 1                  H - 1                F - 1

The empirical formula is CHF

From the mass spectrum attached, the molecular mass of the compound is 64 g/mol

[ 12 + 1 + 19]n = 64

n = 64/32

n = 2

The molecular formula is C2H2F2.

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