In humans, the presence of freckles is a dominant inheritance, and their absence is a recurrent trait. The shape of the eyebrows is also a hereditary characteristic, the separate eyebrows being a dominant characteristic, and the joined eyebrows being a recurring character. In a couple, the woman has freckles and separate eyebrows, and she is heterozygous for both characters. The man does not have freckles, but he has eyebrows closed. How likely is their child to have freckles and separate eyebrows? Use a tree diagram or a Punnett square to justify your answer.

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27-09-2021
Biology

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In humans, the presence of freckles is a dominant inheritance, and their absence is a recurrent trait. The shape of the eyebrows is also a hereditary characteristic, the separate eyebrows being a dominant characteristic, and the joined eyebrows being a recurring character. In a couple, the woman has freckles and separate eyebrows, and she is heterozygous for both characters. The man does not have freckles, but he has eyebrows closed. How likely is their child to have freckles and separate eyebrows? Use a tree diagram or a Punnett square to justify your answer.

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marianaegarciaperedo marianaegarciaperedo · Answer 1 · 2021-09-30T21:54:14+02:00

When crossing a woman -who is heter0zyg0us for freckles and shape of eyebrows- with a man -who is h0m0zyg0us recessive for both traits-, the likelihood of their child to have freckles and separate eyebrows is 1/4 = 25%.

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Available data:

Two diallelic genes ⇒ One of them codes for freckles and the other one for the shape of the eyebrows.

Freckles ⇒ Dominant allele F ⇒ Codes for freckles.

⇒ Recessive allele f ⇒ No freckles.

Eyebrows shape ⇒ Dominant allele E⇒Codes for separate eyebrows.

⇒ Recessive allele e ⇒ Codes for joined eyebrows.

Woman ⇒ Heter0zyg0us for both genes. She has freckles and separate eyebrows.

Man ⇒ H0m0zyg0us recessive for both traits. He does not have freckles, but he has eyebrows closed.

Cross: The woman with the man

Parentals) FfEe x ffee

Gametes) FE, Fe, fE, fe ⇒ woman

fe, fe, fe, fe ⇒ man

Punnett Square) FE Fe fE fe

fe FfEe Ffee ffEe ffee

F1) Genotype:

4/16 = 1/4 = 25% of the progeny will be heter0zyg0us for both traits, FfEe
4/16 = 1/4 = 25% of the progeny will be heter0zyg0us for freckles, but h0m0zyg0us recessive for eyebrow trait, Ffee
4/16 = 1/4 = 25% of the progeny will be heter0zyg0us for eyebrow trait, but h0m0zyg0us recessive for freckles trait, ffEe
4/16 = 1/4 = 25% of the progeny will be h0m0zyg0us recessive for both traits, ffee.

Phenotype:

4/16 = 1/4 = 25% of the progeny will have freckles AND separate eyebrows, FfEe
4/16 = 1/4 = 25% of the progeny will have freckles AND closed eyebrows, Ffee
4/16 = 1/4 = 25% of the progeny will not have freckles AND will have separate eyebrows, ffEe
4/16 = 1/4 = 25% of the progeny will not have freckles AND will have closed eyebrows, ffee

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