Question

How many mL of 6.00 M HCl are needed to prepare 1500 mL of 0.200 M HCl solution?

Answer 1

Answer:

50mL

Explanation:

First find out how many moles will be needed in your final solution.

concentration (c) = Moles / Volume of solution (liters)

or rearrange the formula to find your Moles

Moles = concentration    x    volume of solution

convert your mL to L.  1500 mL is the same as 1.5 L

Moles = 0.200 moles/liter   x   1.5 liter (the liters cancel each other out)

Moles = 0.3 moles

Now use the same formula to determine how much of the original solution you need to end up with what you want.

Rearrange the formula again to solve for the volume.

Volume of solution = Moles / concentration

Volume = 0.3 moles / 6.00 (moles/liter)  here the moles cancel out

Volume = 0.05 L

convert your L into mL

Volume = 50 mL

Answer 2

50 mL of 6.00 M HCl are needed to prepare 1500 mL of 0.200 M HCl solution.

HOW TO CALCULATE VOLUME:

• The volume of solution needed to prepare a diluted solution can be calculated using the following formula:

C1V1 = C2V2

Where;

1. C1 = initial concentration
2. C2 = final concentration
3. V1 = initial volume
4. V2 = final volume

• According to this question, C1 = 6.00 M, C2 = 0.200M, V1 = ?, V2 = 1500mL

• 6 × V1 = 0.200 × 1500

• 6V1 = 300

• V1 = 300/6

• V1 = 50mL

• Therefore, 50 mL of 6.00 M HCl are needed to prepare 1500 mL of 0.200 M HCl solution.

Learn more about how to find volume of solution: https://brainly.com/question/15832344?referrer=searchResults