Question

Calculate the binding energy per nucleon of the Boron isotope B-10 that has a nuclear mass of 10.012937 u.

Remember to identify all of your data, write the equation, and show your work. (mass of proton = 1.007825 u, mass of neutron = 1.008665 u, and 1 u = 931.5 MeV​

Answer 1

From the calculations, we obtain the binding energy per nucleon as 6.475MeV per nucleon.

What is binding energy?

The binding energy is the energy that holds the nucleus together in the nucleus of an atom.

We have the following information;

mass of neutron = 1.008665 u

mass of proton = 1.007825 u

Since there are five protons and five neutrons, the total mass of the nucleons = 5(1.008665) + 5(1.007825) = 5.043325 + 5.039125 = 10.08245 u

Mass defect = 10.08245 u - 10.012937 u = 0.069513 u

Binding energy =  0.069513 u * 931.5 MeV = 64.75 MeV

Binding energy per nucleon = 64.75 MeV/10 = 6.475MeV per nucleon.

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