Question

AABC is an isosceles triangle with AB BC. If AB = 3x + 41, BC = 8x - 54, and AC = 12x - 103,
find x and the measure of each side.

Answer 1

$ab = 3x + 41 \\ bc = 8x - 54 \\ ac = 12x - 103 \\ 3x + 41 = 8x - 54 \\ 54 + 41 = 8x - 3x \\ 95 = 5x \\ x = \frac{95}{5} \\ x = 19 \\ ab = 3(19) + 41 = 98 \\ bc = 8(19) - 54 = 98 \\ ac = 12(19) - 103 = 125$