Question

the average marks of rashid in first four papers is 88 .how much marks should he get in fith paper so that the average of his five papers becomes 90

Answer 1

Answer:

98

Step-by-step explanation:

Average of current papers is:

$\frac{88+88+88+88}{100+100+100+100}$  x 100 = 88

Therefore solve: $\frac{88 + 88 + 88 + 88 + x}{100 + 100 + 100 + 100 + 100}$ x 100 = 90

$\frac{352+x}{500}$ x 100 = 90

352 + x = 450

x = 98

Answer 2

If the average of Rashid's first four score was 88, the number of marks he will need to get in his fifth paper for his average score to be 90 is: 98.

Recall:

Average of a given set of data is calculated as the sum of all the data in the data set divided by the number of data values you have in the data set.

Given that:

Average of Rashid's first four papers = 88

• Let,

$x_1, x_2, x_3, and x_4$ represent the first four scores.

• Average of Rashid's first four scores:

= $\frac{x_1,+x_2 +x_3+ x_4}{4} = 88$

• Multiply both sides by 4

$\frac{x_1,+x_2 +x_3+ x_4}{4} \times 4 = 88 \times 4$

$x_1,+x_2 +x_3+ x_4 = 352$

• This means that the sum of the first four scores = 352

Therefore, let:

• $x_5$ be the fifth score Rashid must score for the average to be 90.

• Thus,

$\frac{352 + x_5}{5} = 90$

• Solve for the score of the fifth paper.

$352 + x_5 = 90 \times 5\\\\352 + x_5 = 450\\\\x_5 = 450 - 352\\\\x_5 = 98$

Therefore, if the average of Rashid's first four score was 88, the number of marks he will need to get in his fifth paper for his average score to be 90 is: 98.

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