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Solving Quadratic Equations by Completing the Square

Answer:

[tex]a = 1[/tex] and [tex]a = -3[/tex]

Step-by-step explanation:

Solving by Completing the Square:

[tex]a^2 +2a -3 = 0 \\ a^2 +2a -3 +3 = 0 +3 \\ a^2 +2a = 3 \\ a^2 +2a +1 = 3 +1 \\ (a +1)^2 = 4 \\ \sqrt{(a +1)^2} = \pm \sqrt{4} \\ a +1 = \pm 2[/tex]

Solving for [tex]a[/tex] from the positive root:

[tex]a +1 = 2 \\ a +1 -1 = 2 -1 \\ a = 1[/tex]

Solving for [tex]a[/tex] from the negative root:

[tex]a +1 = -2 \\ a +1 -1 = -2 -1 \\ a = -3[/tex]

The solutions are [tex]a = 1[/tex] and [tex]a = -3[/tex]

Answer:  a= -3

               a= 1

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