please help me with this question :)

Answer:
[tex] \dashrightarrow \: { \tt{4x + 4 \leqslant 9x + 8}} \\ \\ \dashrightarrow \: { \tt{4x - 9x \leqslant 8 - 4}} \\ \\ \dashrightarrow \: { \tt{ - 5x \leqslant 4}}[/tex]
• divide either sides of the inequality by -5, also the sign will change:
[tex]\dashrightarrow \: { \tt{x \geqslant - \frac{4}{5} }} \\ [/tex]
Answer: x ≥ -4/5
Step-by-step explanation:
Step 1: Subtract 9x from both sides.
Step 2: Subtract 4 from both sides.
Step 3: Divide both sides by -5 and flip the sign.
Therefore, the answer is x ≥ -4/5.