Question

Given f(x)=2x^2-3x+1, determine the value of 3f(-2x)

Answer 1

Answer:

Step-by-step explanation:

3f(-2x)= 3[2(-2x)^2-3(-2x)+1]

         =3[2(4x^2)+6x+1]

         =3[8x^2+6x+1]

         =24x^2+18x+3