Answer:
The amount of air (in grams) is required for an answer. The process is outlined below.
Explanation:
An example for 1 kg of air:
Energy = (specific heat)*(mass)*(temperature change)
Joules = (1.03J/g°C)*(1,000g)*(27°C - 9°C)
Joules = 18540J
Coversion: 1 Joule = 2.78E-07 kwh
Kwh to heat 1 kg of air from 9 to 27°C is 5.15E-03 kwh
Use the same process with the actual mass of air in the house. If you are given house dimensions, calculate the volume and multiply by the density of air to get grams air. (Remember to subtract the volume taken up by household items (e.g., beer cans).
