Question

The empirical formula of a compound is ch2o and its molecular weight is 90. 09 g/mol. Determine the molecular formula.

Answer 1

The molecular formula of the compound is $C_3H_6O_3$

Given the following

The empirical formula of a compound = CH₂O

Molecular formula = 90g/mol

To get the molecular formula, then;

$(CH_2O)_n=90$

Calculate the value of "n"

$(CH_2O)_n=90\\(12+ 2(1)+16)_n=90\\30n=90\\n=\frac{90}{30}\\n=3$

Get the molecular formula:

$=(CH_2O)_3\\=C_3(H_2)_3O_3\\=C_3H_6O_3$

Hence the molecular formula of the compound is $C_3H_6O_3$

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