Taking into account the definition of percent by mass, the percent O and the percent C in limestone are 48% and 12% respectively.
One way to express the composition of the solution is the percent by mass.
The percent by mass (or weight) of a solution is the number of grams of solute in every 100 grams of solution.
The percentage by mass is calculated as the mass of the element or solute divided by the mass of the compound or solute, the result of which is multiplied by 100 to express it as a percentage:
[tex]percentage by mass=\frac{mass of solute}{mass of compound} x100[/tex]
In this case, you know:
Then, the percent O is:
[tex]percentage by mass of O=\frac{1.80 g}{3.75 g} x100[/tex]
percentage by mass of O= 48%
And the percent C is:
[tex]percentage by mass of C=\frac{0.450 g}{3.75 g} x100[/tex]
percentage by mass of C= 12%
Finally, the percent O and the percent C in limestone are 48% and 12% respectively.
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