identify the focus directrix and axis of symmetry of 3x =y2
please help no links!!!
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Answer:
Below in bold.
Step-by-step explanation:
y^2 = 3x is a parabola which is symmetrical about the x-axis and opens to the right.
The general form is y^2 = 4ax where the focus is at (a, 0) and directrix is y = -a.
So for the given parabola, y^2 = 3x:
4a = 3
a = 3/4.
So the focus is (3/4, 0) and directrix is y = -3/4.
Axis of symmetry is y = 0 (that is the x axis).