Question

You have $3000 to use for training your
employees. Each hour of training costs a one
time fee of $200 and then $40 per employee
How many hours of training can you purchase?

Please solve using a system of equations (substitution or elimination)

Answer 1

Answer:

$\frac{75}{no. of employee} - 5$

Step-by-step explanation:

Total we have: 3000

Number of employees = x

Number of hours = y

The equation is:

3000 = (200 + 40y)x

We need to solve for y:

3000/x = 200 +40y

40y = 3000/x -200

$y=\frac{75}{x} - 5$

Therefore, no. of hours = $\frac{75}{no. of employee} - 5$