When burning 180 g of glucose in the presence of 192 g of oxygen, 108 g of water and 264 g of carbon dioxide are produced.
Let's consider the following balanced equation for the combustion of glucose.
C₆H₁₂O₆ + 6 O₂ ⇒ 6 CO₂ + 6 H₂O
According to Lavoisier's law of conservation of mass, matter is neither created nor destroyed in chemical reactions. Thus, the sum of the masses of the reactants before the reaction must be equal to the sum of the masses of the products after the reaction.
[tex]mC_6H_{12}O_6 + mO_2 = mCO_2 + mH_2O\\mCO_2 = mC_6H_{12}O_6 + mO_2 - mH_2O\\mCO_2 = 180g + 192 g - 108 g = 264 g[/tex]
When burning 180 g of glucose in the presence of 192 g of oxygen, 108 g of water and 264 g of carbon dioxide are produced.
You can learn more about Lavoisier's law here: https://brainly.com/question/11429078
