Question

The ground-state electron configuration for an element is
\text{[Ar]}3d^74s^2[Ar]3d
7
4s
2
start text, open bracket, A, r, close bracket, end text, 3, d, start superscript, 7, end superscript, 4, s, squared
You may also see this electron configuration written as
\text{[Ar]}4s^23d^7[Ar]4s
2
3d
7
start text, open bracket, A, r, close bracket, end text, 4, s, squared, 3, d, start superscript, 7, end superscript
Which of the following is the identity of the element?

Answer 1

[Ar]3d⁷4s²is the ground state of Cobalt .

Cobalt has 27 as  atomic number  

So the first 18 is written as [Ar]  at the start of its notation to shows that  it was condense from 1s²2s²2p⁶3s²3p⁶ and written as this noble gas notation before the addition of the remaining 9 as3d⁷4s²

This element, cobalt is a ferromagnetic metal and is located in group VIII of the periodic table.

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