Question

A car is driving at a velocity of 42 m/s. If its brakes can supply an acceleration of -5.0 m/s2,
how much time will be required to bring the car to a stop?
Give your answer in seconds and round to the nearest tenth of a second.
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Answer 1

The time of the car when it comes to a complete stop is 8.4 s.

The given parameters;

• initial velocity of the car, u = 42 m/s

• acceleration of the car, a = - 5.0 m/s²

The time required to bring the car to a complete stop will occur when the final velocity is zero.

Apply the first kinematic equation of motion;

v = u + at

where;

• v is the final velocity of the car when it comes to a complete stop

The time of this motion is calculated as follows;

0 = 42 + (-5)t

0 = 42 - 5t

5t = 42

$t = \frac{42}{5} \\\\t = 8.4 \ s$

Thus, the time of the car when it comes to a complete stop is 8.4 s.

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