The distance traveled by a corn cob that is dropped by Charlotte while traveling down the road at 22 m/s is 13.86 m. The correct option is b.
We can find the distance traveled by the corn cobs with the following equation:
[tex] x_{f} = x_{i} + v_{i_{x}}t + \frac{1}{2}at^{2} [/tex]
Where:
[tex] x_{f}[/tex]: is the final distance =?
[tex] x_{i}[/tex]: is the initial distance = 0 (the point where the corn cob was dropped)
[tex] v_{i_{x}}[/tex]: is the initial speed in the horizontal direction = 22 m/s
a: is the acceleration of the corn cob = 0 (in the x-direction the corn cob is not accelerated)
t: is the time = 0.63 s
Hence, the distance traveled by the corn cob is:
[tex] x_{f} = v_{i_{x}}t = 22 m/s*0.63 s = 13.86 m [/tex]
Therefore, the correct option is b: 13.86 m.
You can find more about horizontal acceleration on a projectile motion here: https://brainly.com/question/13559578?referrer=searchResults
I hope it helps you!