ryinsullivan
ryinsullivan
16-09-2021
Mathematics
contestada
please help, need asap!
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shdhfjjdhsbdhhd
16-09-2021
from equation 2,
y = 10 + 5x/5 - equation 3
substituting equation 3 into equation 1,
21x + 7(10 + 5x/5) = 42
21x(5) + 7(10 + 5x) = 42(5)
105x + 70 + 35x = 210
140x = 210 - 70
140x = 140
x = 1
when x = 1,
y = 10 + 5(1)/5
= 15/5
= 3
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