Question

What is root-16 + root49 written as a complex number in the form a+bi?

Answer 1

Answer:

$→\sqrt{ - 16} + \sqrt{49}$

• We know that, i = √-1
• Form → a + ib

$→( \sqrt{ - 1} \times \sqrt{16} ) + ( \sqrt{49} )\\=i \sqrt{16}+\sqrt{49} \\ = 4i + 7 \\ = \boxed{7 + 4i}✓$

• (7 + 4i) is the right answer.