GIVING 50 POINTS
Find the missing length indicated. Pls show your work
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Answer:
let the missing length =x
Then,by similiarty of triangle
[tex] \frac{6}{15} = \frac{x}{20} [/tex]
[tex]\\ \sf\longmapsto \dfrac{x}{20}=\dfrac{6}{15}[/tex]
[tex]\\ \sf\longmapsto 15x=120[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{120}{15}[/tex]
[tex]\\ \sf\longmapsto x=8[/tex]