Part 1) This image may be the result of the
we know that
The steps to construct a parallel through a point are
1) Using your straightedge, draw a transversal through point P (segment PQ)
2) Using the construction COPY AN ANGLE, construct a copy of the angle formed by the transversal and the given line such that the copy will be located UP at point P. The vertex of the copied angle will be point P.
3) When you draw the line to complete the angle copy, you will be drawing a line parallel to the given line.
therefore
The answer Part 1) is the option
B.) construction of a line parallel to line AB through point P.
Part 2) If m∠RQS is [tex] 75 [/tex]°, then m∠TPU is
we know that
m∠TPU= m∠RQS ------> by corresponding angles
so
m∠TPU=[tex] 75 [/tex]°
therefore
The answer Part 2) is the option
B.) 75