Respuesta :

NaHCO3 = 22.99 + 1.008 + 16(3) = 83.99 g/mol 

Na = 22.99g/83.99 g weight of molecule =.2727 or 27.27% 

3.0 g* .2727 = 0.8211 grams of sodium in sample of NaHCO3 

0.8211 grams Na + 1.266 grams Cl = 2.087 grams

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