Question

Which of the x values are solutions to the inequality 4(2 – x) > –2x – 3(4x + 1)? Check all that apply.
x = –1.1
x = –2.2
x = 0
x = –10
x = 10

Answer 1

Answer:

$x=0$  and  $x=10$

Step-by-step explanation:

The inequality is given as:  $4(2-x)>-2x-3(4x+1)$

Using distributive property [ $a(b+c)=ab+ac$ ] and a little algebra, we have:

$4(2-x)>-2x-3(4x+1)\\8-4x>-2x-12x-3$

Taking all the x's to one side and number to another:

$-4x+2x+12x>-3-8\\10x>-11\\x>\frac{-11}{10}\\x>-1.1$

Now, of the 5 numbers shown, which of them are GREATER THAN $-1.1$ ?

They are 0 and 10.

Answer 2

We are to solve the inequality for the value of x

The options x = 0 and x = 10 represent the value of x

Given:

4(2 – x) > –2x – 3(4x + 1)

open parenthesis

8 - 4x > - 2x - 12x - 3

8 - 4x > - 14x - 3

collect like terms

- 4x + 14x > - 3 - 8

10x > -11

divide both sides by 10

x > -11/10

x > -1.1

All values greater than -1.1 represent x

Therefore, from the options, x = 0 or x = 10

Read more:

https://brainly.com/question/15816805