Question

What is the acceleration of a runner who increases her velocity from 2m/s to 8m/s in 3s?

Answer 1

• initial velocity=u=2m/s
• Final velocity=v=8m/s
• Time=t=3s

$\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}$

$\\ \sf\longmapsto Acceleration=\dfrac{8-2}{3}$

$\\ \sf\longmapsto Acceleration=\dfrac{6}{3}$

$\\ \sf\longmapsto Acceleration=2m/s^2$

Answer 2

Answer: 2 m/s^2

Explanation:

V1-Vf/ T

2m/s - 8m/s / 3s

6m/s / 3s =

2 m/s^2