Question

i need step by step please 3(x-2)^2+1=13

Answer 1

Answer:

$x_{1} = 0. \: \: \: x_{2} = 4$

Step-by-step explanation:

$3(x - 2)^{2} + 1 = 3$

$3( {x}^{2} - 4x + 4) + 1 = 13$

${3x}^{2} - 12x + 12 + 1 = 13$

${3x}^{2} - 12x + 13 = 13$

${3x}^{2} - 12x = 0$

$x \times (x - 4) = 0$

$x = 0$

$x - 4 = 0$

$\boxed{\green{x_{1} = 0. \: \: \: x_{2} = 4}}$