The corresponding angles between parallel lines and a transversal are equal. The value of x is 17
Given that:
[tex]\angle DFG = (2x +6)^o[/tex]
[tex]\angle EFG = (3x -11)^o[/tex]
From the complete question, both angles are corresponding angles.
This means that they are congruent
So:
[tex]\angle EFG = \angle DFG[/tex]
This gives:
[tex](3x -11)^o=(2x + 6)^o[/tex]
[tex]3x -11 = 2x + 6[/tex]
Collect like terms
[tex]3x - 2x = 11 + 6[/tex]
[tex]x = 17[/tex]
Hence, the value of x is 17
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