Question

Jason is pulling a box across the room. He is pulling with a force of 25 newtons and his arm is making a 65 angle with the horizontal, what is the vertical component of the force he is pulling with?

Answer 1

Force=25N

Angle=65

Vertical componenets:-

$\\ \sf\longmapsto Fsin\theta$

$\\ \sf\longmapsto 25sin65$

$\\ \sf\longmapsto 25(0.9)$

$\\ \sf\longmapsto 22.5N$

Answer 2

The vertical component of the force he is pulling is 22.66 N

Given :

A force of 25 newtons and his arm is making an angle of 65 with horizontal.

It forms a right angle triangle with angle 65 degrees.

Force is 25 newtons.

The formula to find vertical component is

$sin( angle )=\frac{vertical force }{force applied} \\sin(angle )=\frac{F_v}{Force}$

Force = 25 N

Angle = 65 degrees

Substitute the given values  

$sin(65)=\frac{F_v}{25} \\25 \cdot sin(65(=F_v\\22.66 Newtons$

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