Respuesta :
Answer:
[tex] \leadsto make \: y \: subject \\ - 3y + 2x = 5y - 8 \\ - 3y - 5y = - 2x - 8 \\ y( - 3 - 5) = - 2x - 8 \\ - 8y = - 2x - 8[/tex]
divide through out by -8 :
[tex]{ \boxed{ \boxed{y = \frac{1}{4} x + 1}}}[/tex]
Answer is b
Answer:
[tex] \leadsto make \: y \: subject \\ - 3y + 2x = 5y - 8 \\ - 3y - 5y = - 2x - 8 \\ y( - 3 - 5) = - 2x - 8 \\ - 8y = - 2x - 8[/tex]
divide through out by -8 :
[tex]{ \boxed{ \boxed{y = \frac{1}{4} x + 1}}}[/tex]
Answer is b