Question

h(t) = 3t2 + 4t
g(t) = t - 1
Find h(g(t))
3t2 - 2t - 1
4+3 - 12t + 1
3t2 + 4t - 1
3t2 - 4t - 1

Answer 1

Answer:

first we need to substitute g(t) value in h(t) value and then evaluate the expression as follows :

h(g(t))=3(t-1)²+4(t-1).

by solving

h(g(t))=3(t²+1-2t)+4t-4

h(g(t))=3t²-2t-1 will.be the final answer