Question

find 2 numbers with a sum of 65. Twice the lesser number is 10 more than the greater number.

Answer 1

Answer:

25 & 40

Explanation:

$x+y=65\\2x-10=y\\\\x=65-y\\130-2y-10=y\\120-2y=y\\120=3y\\y=40\\\\x+y=65\\x+40=65\\x=25$

Answer 2

25 and 40
Bdbsjjd snella a nananana
Skid s