Explanation:
basically, you'll just have to convert the given grams into moles, convert that into moles of Br, and then convert it again into grams of Br
The amount of gram of [tex]Br_{2}[/tex] will be 65.1 grams in equation [tex]2AlCl_{3} + 3Br_{2}[/tex]→ [tex]2AlBr_{3} + 3Cl_{2}[/tex].
The definition of a gram was given as the mass of one cubic centimeter of pure water at 4 degrees Celsius.
Calculation of amount of [tex]Br_{2}[/tex]
The given equation is [tex]2AlCl_{3} + 3Br_{2}[/tex]→ [tex]2AlBr_{3} + 3Cl_{2}[/tex].
The mass of [tex]Br_{2}[/tex] = Count of bromine molecule × molar mass
The mass of [tex]Br_{2}[/tex] = 0.4072 × 159.8
The mass of [tex]Br_{2}[/tex] = 65.08 mol.
The amount of gram of [tex]Br_{2}[/tex] will be 65.1 grams in equation [tex]2AlCl_{3} + 3Br_{2}[/tex]→ [tex]2AlBr_{3} + 3Cl_{2}[/tex].
Therefore, the answer will be option (a).
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