Answer:
[tex]k+(k+2)+(k+4)=87[/tex]
The largest integer is 31.
Step-by-step explanation:
Hi there!
Let k be equal to the smallest of the integers.
Let (k+2) be the next odd integer.
Let (k+4) be the final odd integer.
We're given that the sum of these three integers is 87. Construct an equation:
[tex]k+(k+2)+(k+4)=87[/tex]
Combine like terms:
[tex]k+k+2+k+4=87\\3k+6=87\\3k=81\\k=27[/tex]
Therefore, the smallest integer is 27. Because the largest integer is k+4, the largest integer is therefore 31.
I hope this helps!