nathanmaraj20 nathanmaraj20

31-08-2021
Mathematics

contestada

Find the zeros of ƒ(x) = x3 + 6x2 + 8x.

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SDCInfinity SDCInfinity

31-08-2021

Answer:

-4, -2, 0

Step-by-step explanation:

[tex]x^3+6x^2+8x=0\\\\x(x^2+6x+8)=0\\\\x(x+4)(x+2)=0\\\\x=0\\x=-4\\x=-2[/tex]

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