Question

help pls and thanks!!!

Answer 1

Answer:

y = -3x - 8

Step-by-step explanation:

$y =\frac{1}{3}x+ 2$

Here slope m = (1/3)

Slope of the perpendicular line = $\frac{-1}{m}$ = -1 ÷ $\frac{1}{3} = -1 *\frac{3}{1}= - 3$

Slope m1 = -3 and (-3 ,1)

Equation of line:

y -y1 = m(x -x1)

y - 1 = -3(x - [-3])

y - 1 = -3(x + 3)      

y - 1 = (-3) *x + 3*(-3)

y - 1 = -3x - 9

    y = -3x -9 +1

y = -3x - 8

Answer 2

Answer:

y = - 3x - 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = $\frac{1}{3}$ x + 2 ← is in slope- intercept form

with slope m = $\frac{1}{3}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{\frac{1}{3} }$ = - 3 , then

y = - 3x + c ← is the partial equation

To find c substitute (- 3, 1 ) into the partial equation

1 = 9 + c ⇒ c = 1 - 9 = - 8

y = - 3x - 8 ← equation of perpendicular line