Question

Between what two consecutive integers would the square root of 40 fall?

A. 5 and 6

B 6 and 7

C 7 and 8

D 36 and 49

Answer 1

$\sqrt{40}=\sqrt{2\cdot2^2\cdot5}=2\sqrt{10}$

Notice that $\sqrt{10}\approx3.2$ which means $\sqrt{40}\approx2\cdot3.2\approx6.4$.

So answer is B.

Hope this helps :)