Question

Farah wants to move a 40.0kg rable. She applies a force of 520N. Under these conditions, the table initially moves with an acceleration of 4.50 m/s^2 Calculate the friction force on the table

Answer 1

Answer:

340 Newtons of friction force

Explanation:

4.50 m/s² = 520N of Fn - ?N of Ff ÷ 40 Kg or $\frac{520-x}{40}$ = 4.50

40* 520 - x/40 = 4.50 *40

520-x = 180

520-x/520 = 180/520

x=340 N of Ff