[tex]\large \mathfrak{Solution : }[/tex]
we know,
- [tex]60 \: \: sec = 1 \: \: min[/tex]
- [tex]1 \: \: sec = \dfrac{1}{60} \: \: min[/tex]
- [tex]50 \: \: sec = \dfrac{1}{60} \times 50 \: \: min[/tex]
- [tex]50 \: \: sec = \dfrac{5}{6} \: \: min[/tex]
50 seconds is 5/6 th of a minute.