Answer:
[tex] {y}^{3} + x {e}^{4} = 3 {x}^{2} - 10[/tex]
introduce dy/dx :
[tex] \frac{d( {y}^{3} + x {e}^{4} ) }{dx} = \frac{d( {3x}^{2} - 10) }{dx} \\ \\ 3 {y}^{2} \frac{dy}{dx} + {e}^{4} = 6x - 0 \\ \\ {3y}^{2} \frac{dy}{dx} = 6x - {e}^{4} \\ \\ { \boxed{ \boxed{\frac{dy}{dx} = \frac{6x - {e}^{4} }{ {3y}^{2} } }}}[/tex]
