Question

Please answer quickly

Answer 1

#1

$\\ \sf\longmapsto 0.14(y-7)+0.04y=0.10y-1$

$\\ \sf\longmapsto 0.14y-0.98+0.04y=0.10y-1$

$\\ \sf\longmapsto 0.18y-0.98=0.10y-1$

$\\ \sf\longmapsto (0.18-0.10)y=-1+0.98$

$\\ \sf\longmapsto 0.8y=0.97$

$\\ \sf\longmapsto y=\dfrac{0.97}{0.8}$

$\\ \sf\longmapsto y=1.2$

#2

• Distance in 1h=11/2=5.5miles

Let ones speed =x

others speed=x+1.1

ATQ

$\\ \sf\longmapsto 2x+1.1=5.5$

$\\ \sf\longmapsto 2x=4.4$

$\\ \sf\longmapsto x=2.2$

$\\ \sf\longmapsto x+1.1=3.3$

• Speed of slow hiker=2.2mph
• Speed of fast hiker=3.3mph

#3

• Total distance=2(8+2)=2(10)=20miles
• Time=2h

$\\ \sf\longmapsto Speed=\dfrac{20}{2}=10mph$

Answer 2

If you said please I would have helped u