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Total distance=60m+40m=100m
Total Time=6+4=10s
#a
[tex]\boxed{\sf Speed=\dfrac{Distance}{Time}}[/tex]
[tex]\\ \sf\longmapsto Speed=\dfrac{100}{10}[/tex]
[tex]\\ \sf\longmapsto 10m/s[/tex]
#b
Displacement=AC=60m
[tex]\\ \sf\longmapsto Velocity=\dfrac{Displacement}{Time}[/tex]
[tex]\\ \sf\longmapsto Velocity=\dfrac{60}{10}[/tex]
[tex]\\ \sf\longmapsto 6m/s[/tex]
#C
[tex]\\ \sf\longmapsto Velocity=\dfrac{60}{5}=12m/s[/tex]
#d
The velocity of A to C is greater than Velocity from C to A