What is the equation of the line in point-slope form and slope-intercept form that is
perpendicular to the line
4x - 3y = 30 and passes through the point (-8, 7)?

Respuesta :

9514 1404 393

Answer:

  • y -7 = -3/4(x +8)
  • y = -3/4x +1

Step-by-step explanation:

The slope of a line in the form ...

  ax +by = c

is ...

  m = -a/b

So, the slope of the given line is ...

  -4/(-3) = 4/3

The slope of the perpendicular line is the opposite reciprocal of this,

  m' = -1/(4/3) = -3/4

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The point-slope equation of a line is ...

  y -k = m(x -h) . . . . . . . . line with slope m through point (h, k)

Then your perpendicular line with slope -3/4 through point (-8, 7) is ...

  y -7 = -3/4(x +8)

Rearranging to slope-intercept form, we get ...

  y = -3/4x -3/4(8) +7

  y = -3/4x +1

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